Two astronauts on opposite ends of a spaceship are comparing lunches. One has an
ID: 1465579 • Letter: T
Question
Two astronauts on opposite ends of a spaceship are comparing lunches. One has an apple, the other has an orange. They decide to trade. Astronaut 1 tosses the 0.130 kg apple toward astronaut 2 with a speed of vi,1 = 1.15 m/s . The 0.150 kg orange is tossed from astronaut 2 to astronaut 1 with a speed of 1.23 m/s . Unfortunately, the fruits collide, sending the orange off with a speed of 1.10 m/s in the negative y direction.
Part A: What are the final speed and direction of the apple in this case? Vf,2=
Part B: theta=
Explanation / Answer
m1 = mass of apple = 0.130 kg
m2 = mass of orange = 0.150 kg
V1i = initial speed of apple = 1.15 m/s
V2i = initial speed of orange = - 1.23 m/s
V1f = final speed of apple =
V2f = final speed of orange = - 1.23 m/s
Along X-direction :
0.130 x 1.15 + 0.150 (-1.23) = 0.130 Vx + 0.150 x 0
Vx = - 0.269 m/s
Along Y-direction ::
0.130 x 0 + 0.150 (0) = 0.130 Vy + 0.150 x (-1.10)
Vy = 1.27 m/s
net speed = v = sqrt (1.272 + (-0.269)2) = 1.298 m/s
B )
theta = tan-1(Vx/Vy) = tan-1 (0.269 / 1.27) = 11.96 degree left of positive Y-direction