Two astronauts on opposite ends of a spaceship are comparing lunches. One has an
ID: 1493037 • Letter: T
Question
Two astronauts on opposite ends of a spaceship are comparing lunches. One has an apple, the other has an orange. They decide to trade. Astronaut 1 tosses the 0.130 kg apple toward astronaut 2 with a speed of vi,1 = 1.09 m/s . The 0.170 kg orange is tossed from astronaut 2 to astronaut 1 with a speed of 1.18 m/s . Unfortunately, the fruits collide, sending the orange off with a speed of 0.964 m/s in the negative y direction.
What are the final speed and direction of the apple in this case?
Vf,2 = ??m/s
Part B
counterclockwise from the positive x axis
=Explanation / Answer
here,
mass of apple , ma = 0.13 kg
mass of ornage , mo = 0.17 kg
intial speed of apple , ua= 1.09 i m/s
initial speed of orange , uo = - 1.18 i m/s
final speed of orange , vo = - 0.964 j m/s
let the final speed of apple be va
using conservation of momentum
ma*ua + mo*uo =ma*va + mo*vo
0.13 * 1.09 i - 0.17 * 1.18 = - 0.13*0.964 j + 0.17 vo
vo = (- 0.346 i + 0.765 j )m/s
vo = sqrt(0.346^2 + 0.765^2)
vo = 0.84 m/s
theta = arctan( 0.346/0.765)
theta = 24.34 degree
the final speed is 0.84 m/s and 155.66 degree counterclockwise from +x axis