Two astronauts on opposite ends of a spaceship are comparing lunches. One has an
ID: 1493280 • Letter: T
Question
Two astronauts on opposite ends of a spaceship are comparing lunches. One has an apple, the other has an orange. They decide to trade. Astronaut 1 tosses the 0.130 kg apple toward astronaut 2 with a speed of vi,1 = 1.09 m/s . The 0.170 kg orange is tossed from astronaut 2 to astronaut 1 with a speed of 1.18 m/s . Unfortunately, the fruits collide, sending the orange off with a speed of 0.964 m/s in the negative y direction.
What are the final speed and direction of the apple in this case?
Vf,2 = ??m/s
Part B
counterclockwise from the positive x axis
=Explanation / Answer
m1 = 0.13 Kg
v1i = 1.09 m/s
Assume orange is going from left to right and apple is going from right to left
m2 = 0.170 Kg
v2i = 1.18 m/s
Using momentum conservation,
In Horizontal direction,
m1 * v1i - m2 * v2i = 0.130 * v * cos( )
0.130 * v * cos() = (0.170*1.18) - (0.130*1.09)
v * cos() = 0.453
In Vertical Direction,
0.130 * v * sin() = 0.170 * 0.964
v * sin() = 1.26
= tan^-1(1.26/0.453)
= 70.23 o
v = 1.26/sin(70.2)
v = 1.34 m/s