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An obnoxious brat assigns his 0.0183-kilogram pet mouse Mickey the role of stunt

ID: 1471389 • Letter: A

Question

An obnoxious brat assigns his 0.0183-kilogram pet mouse Mickey the role of stunt mouse by stuffing him into a spring gun and shooting him up into the air at some angle. During the launch process the spring transfers 0.638 J of energy into the 'mouse + Earth + gravitational fields' system. Because he is fired at an angle, when Mickey reaches his maximum height, he is still moving horizontally with a speed of 2.17 m/s. How high above his initial location in the gun does Mickey soar? (In case you are worried, a miniature parachute opens at this point and Mickey lands safely. The brat is slightly less obnoxious than we thought.) Take g = 9.81 m/s^2.

Explanation / Answer

1) energy spring =1/2 kx2

=0.5*0.638*x2

we don't know the x value so we are using work=force*displacemt

W=Fd

d=W/F

here we don't know the F value so

we know newton's second law F=ma using this equation

F=0.0183*2.17

F=0.0397.

this value substituting the above equation

d=0.638/0.397

d=16.07 cm.

so the energy spring=1/2 kx2

=(0.5)*(0.638)*(16.07)2

=82.38

2) Energy that is still K.E=1/2mv2

=(0.5)(0.0183)*(2.17)2

=0.04308

3)The rest of the energy must be in GPE=mgh

=(0.0183)*(9.81)*(6.625*10-34)

= 1.189*10-34

take (2) from (1) and the rem