The meterstick shown to the right is 100 cm long. It is free to pivot around its
ID: 1474826 • Letter: T
Question
The meterstick shown to the right is 100 cm long. It is free to pivot around its center of gravity (CG), which is at the 50-cm mark. There is a 23.0-N block hanging from the 80-cm mark. Decide where each of the other blocks should be placed, one at a time, to balance out the 23.0-N block. At what mark on the meter stick would you place a 16.0-N block to balance the 23.0-N block? (in cm)
At what mark on the meter stick would you place a 44.0-N block to balance the 23.0-N block? (in cm)
20 30 40 50 60 70 80 90 23.0 N 16.0 N 44.0 NExplanation / Answer
equating torque equations about COG
23*30 = 44*A + 16 * B
690 = 44*A + 16 * B
let A = 10 i.e. add 44 to 40 mark
690-440 = 16 B
B=15.625
that means apply 16N at 34.375 mark
now if only 16 newton is used
16*x = 23*30
x=43.125
that is apply 16 N at 6.875 mark
now if only 44 newton is used
44*x = 23*30
x=15.6818181818
that is apply 44 N at 34.3181818182 mark