The meterstick shown to the right is 100 cm long. It is free to pivot around its
ID: 1837102 • Letter: T
Question
The meterstick shown to the right is 100 cm long. It is free to pivot around its center of gravity (CG), which is at the 50-cm mark. There is a 21.0-N block of depleted uranium hanging from the 80-cm mark. One of Dr. Smeevenstein's minions has been tasked with balancing this rod using two other blocks of depleted uranium. At what mark on the meter stick should the minion place a 19.0-N block to balance the 21.0-N block? At what mark on the meter stick would the minion place a 43.0-N block to balance the 21.0-N block?Explanation / Answer
Here ,
W1 = 21 N
for the 19 N block to balance the 21 N block
(50 - x) * 19 - 21 * (80 - 50) = 0
x = 16.84 cm
the position of the 19 N block must be at 16.8 cm
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for the 43 N block
(50 - x) * 43 - 21 * (80 - 50) = 0
x = 35.35 cm
the position of the 43 N block must be at 35.35 cm