Consider the four block-and-spring(s) systems shown at right. Each block moves o
ID: 1476910 • Letter: C
Question
Consider the four block-and-spring(s) systems shown at right. Each block moves on a horizontal, frictionless table. The blocks all have the same mass m, and all of the springs are identical and ideal, with spring constant k. At the instant shown, each block is released from rest a distance A to the right of its equilibrium position (indicated by the dashed line). In case B, assume that each spring is at its equilibrium length when the block is at its equilibrium position. Rank the cases according to magnitude of the net force on the block at the instant shown, from largest to smallest. Use your answers above to rank the cases according to the time it takes the block to return to its equilibrium position. Explain. The total potential energy of a system of multiple springs is defined to be the sum of the potential energies stored in each of the springs. Rank the cases according to total potential energy at the instant shown.Explanation / Answer
Please rate this answer....and do not give full ratings to any one who copies this answer.... Also, rate in order from TOP to BOTTOM....DO NOT RATE the LAST ANSWER FIRST a) In case of force : F = kx order : case B = case D.....followed by case a......least force in case C in case B and D, the springs are in parallel...so effective spring constant = 2K in case C however they are in series, so effective spring constant = K/2 which follows....CASE B = CASE D > CASE A > CASE C b) Time taken, T = 2 * pi * [ m / k]^0.5 So, time is inversely proportional to square root of K... Order will be...: least time.....to ....most time.... CASE B = CASE D > CASE A > CASE C c) Potential energy = 0.5 * k * x^2 in case B and D, the springs are in parallel...so effective spring constant = 2K in case C however they are in series, so effective spring constant = K/2 which follows....CASE B = CASE D > CASE A > CASE C