Choose the correct expression for simple harmonic motion with amplitude 22 cm ,
ID: 1478115 • Letter: C
Question
Choose the correct expression for simple harmonic motion with amplitude 22 cm , frequency 4.0 Hz , and maximum displacement at t=0. Choose the correct expression for simple harmonic motion with amplitude 22 , frequency 4.0 , and maximum displacement at .
( 22 cm )sin[( 4.0 s1)t+3]
( 22 cm )cos[( 8.0 s1 )t]
( 22 cm )sin[( 4.0 s1)t6]
( 22 cm )cos[( 4.0 Hz s1)t]
( 22 cm )sin[( 4.0 s1)t]
Choose the correct expression for simple harmonic motion with amplitude 7.0 cm , angular frequency 8.0 s1 , and maximum velocity at t=0. Choose the correct expression for simple harmonic motion with amplitude 7.0 , angular frequency 8.0 , and maximum velocity at .
( 7.0 cm ) sin[( 4.0 s1 )t]
( 7.0 cm ) cos[( 8.0 s1 )t+4]
( 7.0 cm ) cos[( 4.0 s1 )t]
( 7.0 cm ) sin[( 4.0 s1 )t4]
( 7.0 cm ) sin[( 8.0 s1 )t]
Explanation / Answer
( 22 cm )cos[( 8.0 s1 )t]
because it have maximum displacement at t=0. which is 22 cm
part B
( 7.0 cm ) sin[( 8.0 s1 )t]
will have max velocityat t = 0
becasu V = 7 *8 *cos[( 8.0 s1 )t]
this is at t= 0 , = 56 max velocity