Choose the correct expression for K_eq and description (homogeneous or heterogen
ID: 483295 • Letter: C
Question
Choose the correct expression for K_eq and description (homogeneous or heterogeneous) for the following reaction: 2 C_2H_6(g) + O_z(g) 2 C_2H_4(g) + 2 H_2O(g) Choose the correct expression for K_eq and description (homogeneous or heterogeneous) for the following reaction: 3 Fe(s) + 4 H_2O(q) Fe_3O_4(s) + 4H_2(g) is K_eq = 2.31e + 00 at 4676 K. Calculate K_eq for the reaction 1/2 N_2(g) + 1/2 O_2(g) NO(g) at this temperature and figure out whether the equilibrium favors N_2 and O_2 or NO at this temperature. Pick the correct choice from below.Explanation / Answer
Q.3
Given reaction has all the species in the gaseous state. So we write equilibrium constant expression in the form of kp.
Kp expression for this reaction would be
Keq = P(C2H4)^2 x P(H2O)^2 / ( PC2H6)^2 x PO2
So its given by statement d and statement ‘ e ‘
But we know as its homogeneous reaction so correct statement is “e” .
Answer : “ e”
Q. 4
In this reaction, on reactant is in gaseous phase and other is in solid. So its heterogenous.
Also one product is gas and other is solid. So the Keq expression for it is as follow.
Keq = P(H2) ) ^4 / P ( H2O )^4 ,
Correct answer is option e
Answer: Statement “e”
Q. 5
Given: K eq = 2.31
NO(g) -- > ½ N2(g) + ½ O2 (g) (1)
The reaction we are asked to find Keq for is as follow
½ N2(g) + ½ O2 (g) -- > NO(g) (2)
Reaction 2 is reverse of reaction (1) . We calculate the Keq for the reverse reaction as follow
Keq ( 2) = 1 / Keq (1)
= 1 / 2.31 = 0.4329
The value of Keq of this reversed reaction is less than 1 and therefore the reaction is not spontaneous.
So the option d explains it correctly
Answer : d