Please explain using steps and equations to find the solution! A charged particl
ID: 1479919 • Letter: P
Question
Please explain using steps and equations to find the solution!
A charged particle with a mass of 2·10-3 kg and a charge of 0.5 C moves horizontally at a speed of 6 m/s
and enters a region with an electric field of 4·104 N/C directed vertically up. The region with the field is 50
cm long (horizontal dimension), there is no electric field outside of the region, and there are no
gravitational forces. By what distance does the particle deviate from its original trajectory at the end of the
region? Answer: (c) .035m
A) 0.069 m B) 0.42 m C) 0.035 m D) 6.9x10-5 m E) 3.5x10-5 m
Explanation / Answer
electric force = centripetal force
q*E = m*v^2/R
R = m*v^2/(q*E) = (2*10^-3)*(6^2)/(0.5*10^-6*4*10^4) = 3.6 m
So deviation is 3.6 /100 = 0.036 m
So the answer is C) 0.035 m