In the figure, a uniform rectangular crate 0.40 m wide and and 1.0 m tall rests
ID: 1480127 • Letter: I
Question
In the figure, a uniform rectangular crate 0.40 m wide and and 1.0 m tall rests on a horizontal surface. The crate weighs w, and its and its center of gravity is at its geometric center. A horizontal force F is applied at a distance h above the floor. What minimum value of the coefficient of static friction is requierd to keep the crate from slopping as starts to tip over? Express you answer in terms of h. Follow up: If the block were 3 m tall how would your answer above change, if at all? Explain.Explanation / Answer
Let mue_s is the required minimum coefficient of static friction.
as the crate is in equilibrium, net force and net torque acting on the box must be zero.
Apply, Fnetx = 0
F - w*mue_s = 0
F = w*mue_s
now Apply Net torque about left enge = 0
F*h - w*0.4/2 = 0
F*h = W*0.2
w*mue_s*h = W*0.2
mue_s = 0.2/h <<<<<-------Answer
Follwing up : mue_s does not depend on height of the crate.
It depnds only on h from the ground where we are appying force.
so, mue_s = 0.2/h <<<<<-------Answer