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In the figure, a uniform ladder 12 meters long rests against a vertical friction

ID: 2262482 • Letter: I

Question

In the figure, a uniform ladder 12 meters long rests against a vertical frictionless wall. The ladder weighs 400 N and makes an angle ?, of 78

In the figure, a uniform ladder 12 meters long rests against a vertical frictionless wall. The ladder weighs 400 N and makes an angle ?, of 78 degree with the floor. A man weighing 581 N climbs slowly up the ladder When he has climbed to a point that is 7.8 m from the base of the ladder, the ladder starts to slip. What is the coefficient of static friction between the floor and the ladder?

Explanation / Answer

when man is at 7.8 m from base ,

balancing moment about floor point,

400cos78 x 12/2 + 581cos78 x7.8 = Nwsin78 x 12

Nw = 122.78 N

balancing forces in horizontal ,

f = Nw = 122.78 N

in vertical,

Nf = 400 + 581 = 981 N


f = us. Nf

122.78 = us. x 981

us =0.125