In the figure, a thin glass rod forms a semicircle of radius r = 4.50 cm. Charge

Question

In the figure, a thin glass rod forms a semicircle of radius r = 4.50 cm. Charge is uniformly distributed along the rod, with +q = 4.00 pC in the upper half and -q = -4.00 pC in the lower half.

In the figure, a thin glass rod forms a semicircle of radius r = 4.50 cm. Charge is uniformly distributed along the rod, with +q = 4.00 pC in the upper half and -q = -4.00 pC in the lower half. What is the magnitude of the electric field at P, the center of the semicircle? What is its direction? degree (counterclockwise from the positive x axis)

Explanation / Answer

E=22.626

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