In the figure below, a person of mass m standing on a scale in an elevator (near

Question

In the figure below, a person of mass m standing on a scale in an elevator (near the Earth's surface) that is accelerating upwards with acceleration. The scale shows the person's "weight" to be mg. The scale shows the person's "weight" to be ma. The scale shoes the person's "weight" to be m(g - a). The scale shows the pesron's "weight" to be m(g+a). We cannot tell what the scale would show without more information. In the figure on the right a block of mass m is connected so a black oof mass M > m by a string. Both blocks sit on a frictions floor. in a) a force of magnitude F is expeted on block M pull the system to the right. Is b. a force of the same magnitude F is exerted on block m to pull the system to the left. Circle the true statment The sension T_a greater thanT_0. The sension T_a

Explanation / Answer

2. Applying Fnet = ma in upward direction,

N - mg = ma

N = m(g+a)

and scale will read normal reaction.

so Ans(d)

3.taking both mass as a system,

F = (m+ M)a

a = F / (m + M) this willbe same for both cases.

In case a) using Fnet = ma on m

Ta = ma = mF / (m + M)

In case (b) on M,

Tb = Ma = MF / (m + M )

so Ta < Tb

Ans(b)

4component of force along displacement, = Fcos@

Work done = Fcos@ .L = FLcos@

Ans(c)

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