Refer to the diagrams here. A very large conductive plate of metal (in electrost
ID: 1500043 • Letter: R
Question
Refer to the diagrams here. A very large conductive plate of metal (in electrostatic equilibrium) initially carries a uniform surface charge density of + eta, as shown in the "BEFORE" diagram above. Then an infinite plane of negative charge, with fixed uniform density - eta is placed parallel to the plate, as shown in the "AFTER" diagram above, and the plate is allowed to re-establish electrostatic equilibrium. Assume the following known values: eta, epsilon_o For the "AFTER" situation, use Gauss' Law to find the following (and be sure to show all your steps and reasoning): The electric field values (both magnitude and direction) in each of the regions 1. 2 and 3. The surface charge densities on the two sides of the plate.Explanation / Answer
a) in region 1, E = neta/(2*epsilon) (upward)
in region 2, E = 3*neta/(2*epsilon) (downward)
in region 3, E = neta/(2*epsilon) (downward)
b) the surface charge density on lower surface of the plateplate = +3*neta/2
= +1.5*neta
the surface charge density on upper plate = -neta/2
here charge is redistributed in such a way that electric field inside the conducting slab is zero.