The focal length of the diverging lens here is 57 cm. If tut object with height

Question

The focal length of the diverging lens here is 57 cm. If tut object with height h = 0.8 cm is located at d = 45 cm., what is the height of the image in cm? Positive means upright. 0.4471 0.5231 0.6120 0.7160 08377 09802 1.1468 1.3417 A professor cannot focus her vision on anything that is further away than 1.7 meters. What glasses dots she need (in diopters)? -8 0 -6.4 -1.2 -0.59 2.3 5.8 6.3 7.5 The objective lens in a laboratory microscope has a focal length of 3.30 cm and provides an overall magnification of 1.10-10^2. What is the focal length of the eyepiece if the distance between the two lenses is 29.5 cm? Assume a relaxed viewing distance of 25.0 cm. (in cm) A telescope consists of a mirror with radius of curvature 14 m and an eyepiece of focal length 1.4 cm. Approximately what is the magnitude of its angular magnification? 500 565 638 721 815 921 1041 1176

Explanation / Answer

For diverging lens,

f = - 57 cm

and object distance , do = 45 cm

Applying lens equation to find image distance (di),

1/f = 1/do + 1/di

1/(-57) = 1/45 + 1/di

di = - 25.15 cm

and magnification, m = hi/ho = - (di/do)

hi / 0.8 = - (-25.15 / 45)

hi = 0.4471

Ans (A)

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