Part A What is the minimum potential difference between the filament and the tar

Question

Part A

What is the minimum potential difference between the filament and the target of an x-ray tube if the tube is to accelerate electrons to produce x rays with a wavelength of 0.125 nm ? please answer in kV.

Part B

What is the shortest wavelength produced in an x-ray tube operated at 30.0 kV ? please answer in nm.

Part C

Would the answers to parts (A) and (B) be different if the tube accelerated protons instead of electrons? Why or why not?

Essay answers are limited to about 500 words (3800 characters maximum, including spaces).

Explanation / Answer

The minimum voltage is such that an electron acquires the energy of a photon of the desired wavelength.

Ephoton = hc/ = (1240 eV · nm)/(0.1250 nm) = 9920 eV.

The potential to give an electron this energy is 9.9KeV.

(b) This tube produces electrons of 30 keV, so the cutoff photon energy will be 30 keV. = (1240 eV · nm)/(30 000 V) = 0.0413 nm

c.)No, it would be the same if the tube accelerated protons instead of electrons because the potential energy needed is independent of attribute.

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