Please ignore the written work. The correct answer is B, I just don\'t know how
ID: 1506591 • Letter: P
Question
Please ignore the written work. The correct answer is B, I just don't know how to get it.
A fisherman reels up a 0.21-kg fish hoooked onto his fishing line, giving a vertical impulse of 1.9 Ns to the line. Before the fisherman's reeling, the fish was right under the water surface moving horizontally at 5.5 m/s. Neglect the fish's own weight. How fast does the fish move when it is right above the water surface? Less than 5.0 m/s. Between 5.0 m/s and 10 m/s. Between 10 m/s and 15 m/s. Between 15 m/s and 20 m/s. More than 20 m/s.Explanation / Answer
As the impulse is verticcal the horizontal speed of the fish will not change
The speed attained in the verticle direction will be
Speed = impulse/mass = 1.9/.21 = 9.04 m/s (max speed)
And the horizontal is 5.5 m/s
This gives the net resultant to be 10.58 m/s (max) and 5.5 m/s is the minimum
hence B is correct as the masss of the net line w ill also come in picture