Consider two containers with the same volume and temperature. Container one hold
ID: 1518269 • Letter: C
Question
Consider two containers with the same volume and temperature. Container one holds "dry" air: a mixture of nitrogen and oxygen. Container Two holds "noist" air. The "noist" air has the same ratio of nitrogen to oxygen molecules, but also contains water vapor. According to the ideal gas law, if the pressures are equal, The weight of the gas in Container One will be: lighter than the gas inside the second container, equal to the weight of the gas in the second container, heavier than the gas inside the second container, all the above are incorrect because the pressure cannot be equal.Explanation / Answer
we have to use avagdros law .Avogadro's law states that, "equal volumes of all gases, at the same temperature and pressure, have the same number of molecules". so the number of molecules in both containers is same. the presence of water wapour in container two decreases the density of gas in that. so it will weigh less.so weight of gas in container one will be heavier than the gas in the container two. so option c is correct