Physics Question Please type out all parts to the question. Before copying and p
ID: 1524489 • Letter: P
Question
Physics Question
Please type out all parts to the question. Before copying and pasting your answers for a different problem, please make sure that the given numbers are the same. Solutions that are illegible or have incorrect numbers will be given downvoted.
Three point charges are located at the corners of an equilateral triangle as in the figure below. Find the magnitude and direction of the net electric force on the 1.70 C charge. (Let A = 1.70 C, B = 7.10 C, and C = 4.48 C.)
magnitude N direction ° below the +x-axis 60.00 0.500 m.Explanation / Answer
From the given data,
FAB = k*qA*qB/L^2
= 9*10^9*1.7*10^-6*7.1*10^-6/0.5^2
= 0.4345 N (60 degrees below -x axis)
FAC = k*qA*qC/L^2
= 9*10^9*1.7*10^-6*4.48*10^-6/0.5^2
= 0.2742 N (towards +x axis)
x-component of net force,
Fx = FABx + FACx
= -0.4345*cos(60) + 0.2742
= 0.057 N
y-component of net force,
Fy = FABy + FACy
= -0.4345*sin(60) + 0
= -0.376 N
Net force, F = sqrt(Fx^2 + Fy^2)
= sqrt(0.057^2 + 0.376^2)
= 0.380 N <<<<<<<<<<----------------------ANswer
direction :
theta = tan^-1(Fy/Fx)
= tan^-1(0.376/0.057)
= 81.4 degrees below +x axis <<<<<<<<<<----------------------ANswer