Physics Labs with Computers, Vol P14: Simple Harmonic Motion-Mass on a Spring St
ID: 1865887 • Letter: P
Question
Physics Labs with Computers, Vol P14: Simple Harmonic Motion-Mass on a Spring Student Workbook 012-07000A Class:Phys nol- Date: 7-18-18 Namez Lab Report-Activity P14: Simple Harmonic Motion- Mass on a Spring Pre-Lab Data Table Value Item Equilibrium Position Spring Constant (slope) 5-17 Data Table Mass-.0N kg Peak Time Period (s) Average period of oscillation-4 Calculations Please write your group's solutions and calculations for the following questions on a separate sheet of paper Calculate the theoretical value for the period of oscillation based on the measured value of the spring constant of the spring and the mass on the end of the spring I. 2. Using dimensional analysis, show that the units on the right hand side of the equation above equal the units of the left hand side of the equation. 3. When the position of the mass is farthest from the equilibrium position, what is the velocity of the 4. When the mass is at its farthest from the equilibrium position, calculate the amount of Spring 5. Calculate the absolute value of the maximum velocity of the mass-spring system. mass? Potential Energy, PE, , for the mass-spring system. This is its maximum Spring Potential Energy P14 ©1999 PASCO scientific p. 94Explanation / Answer
1.
m=0.07kg, k=5.17N/m
T=2?*sqrt(m/k)
T = 2?*sqrt(0.07/5.17)
T=0.73s
2.
T=2?*sqrt(m/k)
s = sqrt[kg/(N/m)]
Put N= kg.(m/s)2
s = sqrt[kg/(kg.(m/s)2/m)]
s = sqrt(s2)
3.
For SHM,
v=-A?sin(?t)
Where v=velocity, A= amplitude, ?=angular velocity, t=time
At farthest point sin(?t) = 0
hence,
v=-A?sin(?t) = 0 = vmin
Thus at farthest point velocity is minimum.
4.
By law of conservation of energy for spring-mass system,
Enet = KE+PE
Enet = 1/2mv2 + 1/2kx2
At farthest point v=vmin = 0 m/s and x=A
Hence,
Enet = 1/2kA2
It means at farthest point mass is at it’s farthest point or amplitude.
So the mass at this point has maximum PE value = Enet