Can someone please help me with PART F & PART G please! Learning Goal: To be abl
ID: 1526170 • Letter: C
Question
Can someone please help me with PART F & PART G please!
Learning Goal: To be able to calculate the energy of a charged capacitor and to understand the concept of energy associated with an electric field. The energy of a charged capacitor is given by U = QV/2, where Q is the charge of the capacitor and V is the potential difference across the capacitor. The energy of a charged capacitor can be described as the energy associated with the electric field created inside the capacitor. In this problem, you will derive two more formulas for the energy of a charged capacitor; you will then use a parallel-plate capacitor as a vehicle for obtaining the formula for the energy density associated with an electric field. It will be useful to recall the definition of capacitance. C = Q/V, and the formula for the capacitance of a parallel-plate capacitor, C = Q/V, where A is the area of each of the plates and d is the plate separation. As usual, _0 is the permittivity of free space. Part F A parallel-plate capacitor has area A and plate separation d, and it is charged so that the electric field inside is E. Use the formulas from the problem introduction to find the energy U of the capacitor. Part G Find the energy density u of the electric field in a parallel-plate capacitor. The magnitude of the electric field inside the capacitor is E.Explanation / Answer
F) potential energy stored in the capacitor,
U = (1/2)*C*V^2
= (1/2)*(A*epsilon/d)*(E/d)^2
= (1/2)*A*d*epsilon*E^2
G) energy density, u = total potential energy stored/volume of the cpacitor
= (1/2)*A*d*epsilon*E^2/(A*d)
= (1/2)*epsilon*E^2