MasteringPhysics Homework 3 Chapter 18 cument and ohm\'s Law-Google Chrome Secur

Question

MasteringPhysics Homework 3 Chapter 18 cument and ohm's Law-Google Chrome Secure l PHY2054 View? assignment ProblemlDa 72930728&offset; next College Physics 2 Spring 2017 Help Close Item 18 Resources Item 18 e previous l 18 of 18 I return to assignment chageti An whose peak value is 230 v.is across a 3100 resistor Part A What is the peak cument in the resistor? Express your answer to two significant figures and include theappropriate units. ON a Value Units Submit My Answers Gere Part B What ls the mms current in the resistor? Express your answer using two significant figures. Palme Answers A D A 400

Explanation / Answer

For peak:

V=IR

230 V = I * 310 ohms

I is 0.741 amps.

The RMS stands for root mean square. It's a statistical measure of how much current is flowing through the system. Imagine if you took the sine wave AC currents usually make, cut the tops off the waves and stuck them in the troughs so you'd get a smooth line. This sounds complicated but mercifully all you have to do is divide your current by the square root of 2. It really is that easy.

0.742 amps / sqrt(2) = 0.525

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