For the calculations below, use the following slider settings. Initial position
ID: 1526839 • Letter: F
Question
For the calculations below, use the following slider settings. Initial position of car 1 = +22.0 m; Velocity of car 1 = +9.00 m/s; Acceleration of car 2 = +0.700 m/s/s. Note that car 2 starts from rest with an initial position of 0 m. With these settings, car 2 will not catch car 1 before the simulation stops, but assume that the motions continue beyond this point. However, you can use the simulation with different settings to test your ideas about when something will happen. At what instant will car 1 be farthest ahead of car 2? What is the maximum distance that car 1 will be ahead of car 2?
Explanation / Answer
A) when the velocity of car 2 is equal to 9.00 m/s,car 1 be farthest ahead of car 2.
let t is the time taken the above thing to happen.
v2 = vo2 + a*t
9.00 = 0 + 0.700*t
==> t = 9.00/0.700
= 12.8 s <<<<<<<<<<---------------Answer
B) maximum distance between the car 1 and car2,
d_max = d + (distance travelled by car 1 - distance travelled by car 2)
= d + (v1*t - vo2*t + (1/2)*a*t^2)
= 22 + (9*12.8 - 0 + (1/2)*0.7*12.8^2)
= 194 m <<<<<<<<<<---------------Answer