Physics SHM along wave Two points, A and B, on the surface of earth at at longit
ID: 1527119 • Letter: P
Question
Physics SHM along wave
Two points, A and B, on the surface of earth at at longitude and 60 degrees apart in latitude. An earthquake...
The answers should be :
S T smart oscillations a) If its length is increased by 508 what is its new b) period in terms of its 2 Given the radius of period T a simple pendulum the Earth explain hOR Earth could be used to measure the mass of the Two points A and B on the surface of Earth are at the longitude and 60.0 apart in latitude An earthquake A P-wave that point B by traveling straight through the body of Earth. at a con stant speed of 7.80 km/s The earthquake also creates a Rayleigh wave which only travels along the surface of Earth at a speed of 4.50 km/s a) Which of these two seismic waves arrives at B first b) What is the time difference between the arrivals of the two waves at B? The radius of Earth is 6,370 km A wave pulse travels at 5.00 m/s along a horizontal string which is 50.0 cm long with a mass of 3.00 g Another string has the same length but half the mass of the first If both strings are under the same tension what is the speed of a wave pulse propagated along the second string? Two cables of equal diameter and length, one made out of aluminum and the other out of steel are welded togetherExplanation / Answer
Taking your radius figure, the earth's diameter is 12,740 km.
Therefore its circumference is 12,740 x Pi = 40,024 km.
Halve that, one longitude must be 20,012 km.
This is divided into 180 deg., so 1 deg latitude = 111.118 km.
So 60 deg. of latitude is 6667.08 km.
The Rayleigh wave travels at 4.5 km/sec., so dividing, it arrives 1481.57 secs. later.
The P wave travels along the straight line difference between the 2 points 60 deg. apart, So you need chord length.
2r sin (c/2) = (6370 x 2) x (sin 60/2).
= 6370 km.
Dividing this by 7.8, = 816.67 secs.
1481.57 -816.67 = 664.90 secs. the Rayleigh wave arrives after the P wave.
About 11.08 minutes.