Problem 17: In the figure, the point charges are located at the corners of an eq

Question

Problem 17: In the figure, the point charges are located at the corners of an equilateral triangle 26 cm on a side.

Part (a) Find the magnitude of the electric field in N/C at the center of the triangular configuration of charges, given that qa = 1.5 nC , qb = -9.7 and qc = 1.6 nC . Numeric : A numeric value is expected and not an expression. |E| = __

Part (b) Find the direction of the electric field in degrees below the horizontal. Numeric : A numeric value is expected and not an expression. = _

physics

Explanation / Answer

the center is given by ---

R =a sqrt (3) /3

=0.15m

Field due to qA=1.5nC

E=ka/r2

=9e9x1.5e-9/0.15x0.15 = 600 N/C

Field due to qB=.-9.7nC

9e9x9.7e-9/0.15x0.15 = 3880 N/C

X component = 3880 cos30 =3360.18

Y component= 3880 sin 30 = 1690

Field due to qC =1.6nC

9e9x1.6e-9/0.15x0.15

=640 N/C

X component = 640 cos30=554.26 N/C

Y component=640 sin30=320 N/C

Total in x direction = 554.26 +3360.18 =3914.44 N/C

Total in y direction = 1690 +600 -320 = 1970 N/C

Total Electric field on the mid point = sqrt {(3914.44)^2 + (1970)^2}

=4382.21 N/C

B) direction theta = arctan 1970 /3914.44 =63.285 below x axis

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