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Part II: Change Launch Angle Setup Line of Sight T.O.F. Pad Procedure 1. Put the

ID: 1527787 • Letter: P

Question

Part II: Change Launch Angle Setup Line of Sight T.O.F. Pad Procedure 1. Put the plastic ball into the projectile launcher. Cock the launcher to the short-range position 2. Test fire the ball to determine where to place the timing pad on the floor. Put the timing pad on the floor where the ball hits 3. Reload the ball into the projectile launcher, and cock the launcher to the short-range position. Click "Start' to begin recording data. 4. Shoot the ball on the short-range position. After the ball hits the time-offlight pad, click 'Stop. Record the initial speed and the time of flight. 5. Repeat steps 1-4, but adjust the angle of the launcher to 15°, 30° and 45° above horizontal. Arrangement Initial Speed (m/s) Time of Flight (s) Short range, Horizontal 2.8 0.25 Short range, 15 3.6 0.30 2.9 0.40 Short range, 30 Short range, 45 3.1 0.50 Predict the Range NOTE: Enter the results from each of the following steps in Table 1. 1. Record the height of the launcher, d, as indicated in the image below.

Explanation / Answer

initial speed= vo= 2.9 m/s and theta=30

so initial vertical speed = vo sin 30 = 2.9 sin 30= 1.45 m/s.

time to reach the maximum height.

Vfy= Vo + gt

0=1.45+ (-9.8)t

t=0.148 s .

Maximum height.

y= viy t+ 0.5 gt^2

Y= 1.45 (0.148)+0.5(-9.8)(0.148)^2

y=0.107 m.

time take to fall from maximum height is sameas the time to reach the maximum height. so t=0.148 seconds .

total time of flight= time to reach max hieght+ time to fall= 0.148+ 0.148=0.296 s.

range= Vox T = 2.5(0.296)= 0.74 m .

question

short range, horizontal time= 0.25s

short range, 30degrees time= 0.40 s

difference=0.40-0.25= 0.15s

so time of flight of short range, horizontal is 0.15 s less than the time of short range 30 deg.so option c is correct