In the standard Mass Spectrometer Setup before entering the magnetic field zone
ID: 1527970 • Letter: I
Question
In the standard Mass Spectrometer Setup before entering the magnetic field zone where its trajectory is determined by the Lorentz Force the charged particles pass through the velocity selector. In it, the electric force acts on particles in the direction opposite to the magnetic force. After travelling along the straight line in the velocity selector employing E-field of magnitude of 1000N/C, the carbon ion (12C)^+ travels inside the spectrometer along the circular path of radius r= 1.5m. Find the velocity of the ion as it leave the velocity selector.Explanation / Answer
force imparted due to electric field= qE = (1.6 x 10^-19) ( 1000)
centripetal force = mv^2/ r
mass of carbon atom = 1.9927 x 10-26 kg
1.6 x 10^-16 = ( 1.99 x 10^-26 ) ( v^2)/ 1.5
v^ 2= 1.206 x 10^ 10
v= 1.1 x 10^5 m/s apprx