In the drawing below, E = 4.0N/C and d = 1.5m. Calculate the work done by the el

Question

In the drawing below, E = 4.0N/C and d = 1.5m. Calculate the work done by the electric field in moving a +5.0 times 10^C charge from A to B. Be sure to include - sign If your answer Is negative. Your answer needs to be in J but you don't need to enter the unit in your answer for this question. Note: the answer for this question is very small and using scientific notation will help. This system uses E in place of x10 so for example to enter 3 times 102?24 type 3E-24 in the answer box. In the situation in diagram c above, calculate the potential energy difference between the +5.0 times 10^?9C charge at B and at A. Be sure to include - sign if your answer is negative. Your answer needs to be in J but you don't need to enter the unit in your answer for this question. Note: the answer for this question is very small and using scientific notation will help. This system uses E in place of x10 so for example to enter 3 times 10-24 type 3E-24 In the answer box. For the situation in diagram c above, calculate the potential difference between A and B. Be sure to include - sign if your answer is negative. Your answer needs to be in V but you don't need to enter the unit in your answer for this question. How much work is done moving a charge along an equipotential surface (line)? Explain

Explanation / Answer

force on the charge=q*E

work done=dot product of force and displacement

=force*distance*cos(angle between displacement and force)

=charge*E*distance*cos(30)

=5*10^(-9)*4*1.5*cos(30)=2.598*10^(-8) J

Q11.

potential energy at A - work done by the elctric force=potential energy at B

==>potential energy at A -potential energy at B=2.598*10^(-8) J

Q12. potential at A-potential at B=(potential energy at A-potential energy at B)/charge=5.196 volts

Q13. along a equipotential line, work done=0

as work done=charge*potential difference

and along an equipotential line, potential are all equal and hence potential difference=0 ==>work done=0

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