Remarks Because the impact is inelastic, it would be incorrect to equate the ini
ID: 1529618 • Letter: R
Question
Remarks Because the impact is inelastic, it would be incorrect to equate the initial kinetic energy of the incoming bullet to the final gravitational potential energy associated with the bullet-block combination. The energy Isn't conserved! Question The ways that mechanical energy is lost from the system in this experiment include: (Select all that apply.) energy loss because the kinetic energy of the bullet becomes the kinetic energy of the block and bullet. deformation of the bullet as It enters the wood, work m deforming the block. friction to bring the bullet to a stop relative to the ground. energy loss from the change in height of the block. friction to bring the bullet to a stop relative to the block. Use the worked example above to help you solve this problem. The ballistic pendulum (see figure a) is a device used to measure the speed of a fast-moving projectile such as a bullet. The bullet is fired into a large block of wood suspended from some light wires. The bullet is stopped by the block, and the entire system swings up to a height h. It is possible to obtain the initial speed of the bullet by measuring h and the two masses. As an example of the technique, assume that the mass or the bullet, m_1 is 5.04 g, the mass of the pendulum, m_2, is 1.039 kg, and h is 5.14 cm. Find the initial speed of the bullet, v_1 i m/s A bullet with mass 4.56 g is fired horizontally into a 1.980-kg block attached to a horizontal spring. The spring has a constant 6.40 times 10^2 N/m and reaches a maximum compression of 5.88 cm. Find the initial speed of the bullet-block system. Find the speed of the bullet.Explanation / Answer
1) deformation of bullet as it entres the wood .
work in deforming the block .
friction to bring bullet to stop relative to block .
2) Here, 1/2 * 1.044 * v2 = 1.044 * 9.8 * 0.0514
=> initial speed of bullet , v = 1.0037 m/s
3) a) Here, 1/2 * 1.9845 * v2 = 1/2 * 640 * 0.0588 * 0.0588
=> v = 1.056 m/s
Thus, initial speed of bullet block system = 1.056 m/s
b) speed of bullet = (1.9845 * 1.056)/(4.56 * 10-3)
= 459.57 m/s