Consider the arrangement shown in the figure above. Block A has m_A 40kg, blocks
ID: 1531839 • Letter: C
Question
Consider the arrangement shown in the figure above. Block A has m_A 40kg, blocks 2.0kg. The coefficient of kinetic friction between bloke B and the horizontal plane is a so. The nattier friction coefficient Dot large enough to keep the blocks at rest, and this the blocks are aiding (block A is sliding downhill, block B wilding to the 1et). The inclined plane is frictionless and at angle e 30 The pulley is massless and frictionless and only serves to change the direction of the cord connecting the blocks. The cord has negligible Find the acceleration of the blocks. To receive credit, you must show all your work, using the Waal stress of 1) carefully drawing the free-body diagrams, 2 writing down Newton's second law in component form separately for each block, 3) solving the resulting set of equations, working in variables only (do not plug in numbers yet), and finally 4) inserting the given numerical values.Explanation / Answer
let a be the accelration of the system
for A
mA*g*sintheta - T = mA*a .............(1)
for B
T - fk = mB*a
T - uk*mB*g = mB*a .............(2)
solving 1 & 2
mA*g*sintheta - uk*mB*g = a*(mA+mB)
a = ( mA*g*sintheta - uk*mB*g )/(mA+mB)
a = ((4*9.81*sin30)-(0.5*2*9.81))/(4+2)
acceleration a = 1.635 m/s^2 <<<<----answer