Answer part b A permanent dipole consists of a point charge of +2 times 10^-9 C
ID: 1532595 • Letter: A
Question
Answer part b
A permanent dipole consists of a point charge of +2 times 10^-9 C located at (0, 1, 0) mm and a point charge of -2 times 10^-9 C located at (0, 1, 0) mm What is the dipole moment of this dipole? (Remember that the dipole moment is a vector quantity.) What is the electric field of the dipole at the location (20, 0, 0) cm? A small plastic cube is at the location (0, 4, 0) cm, i e. on the axis of the dipole cube distance that is 20 times the size of the dipole. Draw a square to represent the cube, and sketch its polarization. Indicate the direction of the y-axis. A small cube is at the location (-4, 0, 0) cm, i. e. on the perpendicular bisector of the axis of the dipole at a distance that 20 times the size of the dipole. Draw a square to represent the cube, and sketch its polarization. Indicate the direction of the -x-axis.Explanation / Answer
a) dipole moment is p = q*l = 2*10^-9*(2*10^-3) = 4*10^-12 C-m
b) Field on the equitorial line due to dipole is E = k*p/r^3
E = (9*10^9*4*10^-12)/(0.2^3) = 4.5 N/C