Assuming no missing principal maxima, how many secondary maxima will there be be

Question

Assuming no missing principal maxima, how many secondary maxima will there be between principal maxima in a 5-slit diffraction slide? A 625 nm laser is passed through a 4-slit diffraction slide with slit width, a = 0.040 mm, and distance between slits, d = 0.020 mm, to a screen Z = 1.0 m away. At the position x = (625 times 10^-9 m) times (1.0 m)/0.020 times 10^-3 m (c) a minimum or zero? A laser with a wavelength of 600 nm is passed through a diffraction grating with 600 lines per mm. How far from the grating must you place a screen with width w = 30 cm (width, not thickness) to just barely see both the left and right m = 2 maxima on the edges of the screen? Assume the setup is similar to Figure 8, except the distance between the grating and the screen is unknown.

Explanation / Answer

#4 Between two principal maxima there are N-1 zeros and N-2 secondary maxima. So here, there would be 5-2 =3 secondary maxima

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