If the frequency of a sound wave hitting the eardrum is doubled while the amplit

Question

If the frequency of a sound wave hitting the eardrum is doubled while the amplitude remains same, the maximum of vibration of the eardrum and the maximum acceleration of velocity vibration of the eardrum become _____ times and _____ times respectively. a. 2, 2 b. 2, 4 c. 4, 4 d 4, 2 e. Do not change What are the average speed and average velocity (magnitude) over 1 cycle for system mass, system with amplitude A and angular frequency? a. Avg speed = 0.50 magnitude velocity of avg. velocity = 0.54 b. Avg speed = magnitude velocity of avg. velocity = c. Avg speed = 0 magnitude velocity of avg. velocity = 0 d. Avg speed = 0.644 magnitude velocity of avg. velocity = 0 e. Avg speed = magnitude velocity of avg. velocity = 0.54 The intensity of the sound wave from an airplane at a distance of 150 m is 103 W/m^3. What is the intensity of the sound wave that reaches the ground when the airplane overhead at an altitude of 10.70 km? Assume that the sound wave radiates from the airplane equality in all direction. a. 1.47 mW/m^2 b. 3.43 mW/m^2 c. 1.52 mW/m^2 d. 2.12 mW/m^2.

Explanation / Answer

7)

velocity is directly proportional to frequency. Therefore, maximum velocity will be doubled

acceleration is directly proportional to square of frequency, Therefore, maximum acceleration will be quadrupled

option (b) is the correct answer

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8) Time period = 2/

Total distance covered in one time period = 4A

average speed = total distance/ total time = 4A/(2/) = 0.64A

Total displacement in one time period = 0

Average velocity = total displacement/total time = 0

option (d) is the correct answer

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9) Intensity is inversely proportional to square of distance

I = k/d2

=> 10.3 = k/(1302)

=> k = 174070

When d = 10.7 km = 10700 m

I = 174070/(107002)

=> I = 0.0015 W/m2 = 1.5 mW/m2

option (c) is the correct answer

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