If the frequency of the c allele is .15, what is the frequency of the C allele?
ID: 168012 • Letter: I
Question
If the frequency of the c allele is .15, what is the frequency of the C allele? The frequency of the A allele is 0.6 in a population of 80 individuals. How many individuals will have the a "allele" in their genome? The frequency of the A allele in a population is 0.6. What would you expect to be the genotype of this particular population of 100 individuals? A population has been genotyped and it was found that 50 individuals had the AA genotype, 70 individuals had the Aa genotype and 20 individuals had the aa genotype. What is the frequency of the two alleles? More problems... Determine the frequency for the following alleles if: a. What is a if A is .67 b. What is B if b is .21 c. What is c if C is 1 d. What is D if d is .35 Determine how many individuals in question 1 have the a. a allele in a population of 110. B. B allele in a population of 50. c. c allele in a population of 550. d. D allele in a population of 4, 545. Determine the genotypes of individuals in #2 (frequency and number of individuals). Determine the frequency of the two alleles given the following genotypes. a. 60 individuals with AA genotype, 90 with the Aa genotype, 30 individuals with an aa genotype. b. 80 individuals with BB genotype, 140 individuals with Bb genotype, 50 individuals with a bb genotype. c. 450 individuals with CC genotype, 600 individuals with Cc genotype, 210 individuals with cc genotype. d. 1, 250 individuals with DD genotype, 2, 500 individuals with Dd genotype, 800 with dd genotype.Explanation / Answer
Answer:
1. Frequency of c allele (q) = 0.15
p + q = 1 (HW equilibrium)
So, p = 1-q = 1-0.15 = 0.85
Frequency of C allele = 0.85
2. Frequency of A allele = 0.6
So, frequency of a allele = 1 - 0.6 = 0.4
Total population = 80
So, number of individuals with a allele = 0.4 * 80 = 32
3. Frequency of A allele = 0.6
Frequency of a allele = 0.4
Frequency of genotypes: AA = (0.6)2 = 0.36
So, number of AA individuals = 0.36 * 100 = 36 individuals
aa = (0.4)2 = 0.16
So, number of aa individuals = 0.16 * 100 = 16 individuals
Aa = 2 * 0.6 * 0.4 = 0.48
So, number of Aa individuals = 0.48 * 100 = 48 individuals
4. AA = 50, Aa = 70, aa = 20
Total = 140
Frequency of AA = 50/140 = 0.3571
So, A = Frequency of AA = 0.5975
Frequency of aa = 20/140 = 0.1428
So, a = 0.3779