In the figure below, a chain consisting of five links, each of mass 0.107 kg, is

Question

In the figure below, a chain consisting of five links, each of mass 0.107 kg, is lifted vertically with a constant acceleration of magnitude a = 2.57 m/s2.

(a) Find the magnitude of the force acting between link 1 and link 2.

(b) Find the magnitude of the force acting between link 2 and link 3.

(c) Find the magnitude of the force acting between link 3 and link 4

(d) Find the magnitude of the force acting between link 4 and link 5.

(f) Find the magnitude of the net force accelerating each link.

Explanation / Answer

here,

acceleration, a = 2.57 m/s^2

mass of each link, m = 0.107 kg

solving by assuming link1 to be lowest and link5 to be highest link in chain

Part a:
Net force = Force on chain 2 + forcec on chain 1
Net force = 0.107 * 2.57 + 0.107 * 9.81
Net force = 1.325 N

Part B:
Net force = 1.325 + 0.107 * 2.57 + 0.107 * 9.81
Net force = 2.65 N

Part C:
Net force = 2.65 + 0.107 * 2.57 + 0.107 * 9.81
Net force = 3.975 N

part D:
Net force = 3.975 + 0.107 * 2.57 + 0.107 * 9.81
Net force = 5.3 N

part E:
Net force = 5.3 + 0.107 * 2.57 + 0.107 * 9.81
Net force = 6.625 N

Part F:
Net force on each link = mass * acceleration
Net force on each link = 0.107 * 2.57
Net force on each link = 0.275 N

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