Please include formulas used, thank you! A 3.0- mu F capacitor (C1)is connected

Question

Please include formulas used, thank you!

A 3.0- mu F capacitor (C1)is connected to a 12-V battery A) Find the energy stored in the capacitor B) The capacitor is disconnected from the battery, then the space between the plates is filled with a dielectric k=1.5. Find the new value of the energy stored in the capacitor. C) A second capacitor (C=1 mu F), that carries no charge, is then connected to the first capacitor as shown below. Find the electric charge and potential difference across each capacitor after the equilibrium is reached. Answer: A)2.16*10^-4J; B) 1.44*10^-4J; C) Q1=29.45 mu C; Q2=6.54 mu C; delta V1=delta V2=6.54V

Explanation / Answer

A)

energy stored, U=1/2*C*v^2

U=1/2*3*10^-6*12^2

U=2.16*10^-4 J

B)

U'=U/K

U'=(2.16*10^-4)/(1.5)

U'=1.44*10^-4 J

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