Coulomb\'s law for the magnitude of the force F between two particles with charg
ID: 1572379 • Letter: C
Question
Coulomb's law for the magnitude of the force F between two particles with charges Q and Q' separated by a distance d is |F| = K |QQ'|/d^2, where K = 1/4 pi sum_v, and sum_0 = 8.854 times 10^-12 C^2/(N. m^2) is the permittivity of free space. Consider two point charges located on the x axis: one charge, q_1 -15.5 nC, is located at x_1 = -1.685 m; the second charge, q_2 = 37.0 nC, is at the origin (x = 0.0000). What is the net force exerted by these two charges on a third charge q_3 = 54.5 nC placed between q_1 and q_2 at x_3 = -1.215 m? Your answer may be positive or negative, depending on the direction of the force. Express your answer numerically in new tons to three significant figures.Explanation / Answer
Here ,
for the net force on the charge q3
net force on the charge q3 = F13 + F23
net force on the charge q3 = -9 *10^9 * 10^-9 * 10^-9 * 54.5*(15.5/(1.215 - 1.685)^2 + 37/1.215^2)
net force on the charge q3 = -4.67 *10^-4 N
the net force on the charge q3 is -4.67 *10^-4 N