Please explain. Thank you for your help! A parallel-plate capacitor is made of t
ID: 1575196 • Letter: P
Question
Please explain. Thank you for your help!
A parallel-plate capacitor is made of two conducting plates of area A separated by a distance d. The capacitor carries a charge Q and is initially connected to a battery that maintains a constant potential difference between the plates. The battery is then disconnected from the plates and the separation between the plates is doubled. 1) Which of the following remains constant? OVoltage across the capacitor OCapacitance of the capacitor Charge on the capacitor (Survey Question) 2) Briefly explain your answer to the previous question. Submit 3) The electric potential energy stored in the capacitor will: O stay the same O increase O decrease Submit (Survey Question) 4) Briefly explain your answer to the previous question.Explanation / Answer
(1)
Charge on the capacitor will remains same.
(2)
Explaination - Since battery is disconnected, there is no source for charge to decrease or increase. so, total charge
on capacitor will remains same
(3)
Electric potential energy stored in capacitor will decrease
(4)
Explaination -
PE = (1/2)CV^2
And Capacitance C = eo*A / d
As seperation b/w plates is doubled, capacitance is half of previous value
means it decreases.
Thats why PE will decrease