A skater descends down a slope at an angle 22 degrees to the horizontal. If the

Question

A skater descends down a slope at an angle 22 degrees to the horizontal. If the skater’s change in altitude (vertical distance) is 55.0 meters downward, 1. How far has she traveled along the slope? 2. How far has she traveled horizontally? 3. Sketch a DISPLACEMENT vector of skater A skater descends down a slope at an angle 22 degrees to the horizontal. If the skater’s change in altitude (vertical distance) is 55.0 meters downward, 1. How far has she traveled along the slope? 2. How far has she traveled horizontally? 3. Sketch a DISPLACEMENT vector of skater 1. How far has she traveled along the slope? 2. How far has she traveled horizontally? 3. Sketch a DISPLACEMENT vector of skater

Explanation / Answer

1. H/L = sin22

=> L = 55/sin22 = 146.82 m

2. R = Lcos22 = 146.82cos22 = 136.13 m

3. L will be the displacement vector (vector along the slope from top to bottom)

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