Part A Determine the average magnitude of the E f eld across a body cell membran
ID: 1577328 • Letter: P
Question
Part A Determine the average magnitude of the E f eld across a body cell membrane. A 0.11 actually somewhat larger). potential difference exists from one side to the other and the membrane 7.0 × 10 m thick. Assume that the die constant is 1.0 it is Express your answer to two significant figures and include the appropriate units. E-1 Value Units Submit Incorrect: Try Again; 5 attempts remaining Part B Determine the magnitude of the electrical force on a sodium ion (charge +e) in the membrane. Express your answer to two significant figures and include the appropriate units. Fed. e = Value Units Submit Request AnswerExplanation / Answer
potential difference = delta v = 0.11 v
thick ness = d = 7 x10^-9 m
a) magnitude of electric field = E = V /d = 0.11 / 7*10^9 = 0.0157 x10^9 N/C
B) Force = F = EQ = 0.0157 x10^9 * 1.6 X 10^-19 = 0.025 X10^-10 N