Student Data Students are to complete tables 3 and 4 Table 3: Student Data-Speed

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Student Data Students are to complete tables 3 and 4 Table 3: Student Data-Speed of the Ball by the Projectile Method Speed of Range Range Height Height Time of Fall the Ball (cm/s) Average 12743 223 92.2 2 e 63AS 2 267 222 1924 2 04 635 216 423922 6 Table 4:Student Data-Speed of the Ball before Collision by the Momentum Method Mass of the pendulumm Mass ofthe ball ·m Speed of the Pendulum Speed of the Ball Average & Ball After Collision Before Collision Average (cm) (cm/s) 1 6. 19 127.55 2122 % Difference between vap and vbm- Calculations Show all calculations. If you do calculations on a spreadsheet, the calculation will then be an integral part of the spreadsheet and need not be shown here Post-lab Questions What is the initial vertical speed of the ball when it is shot on the floor? 2 What is the momentum of a car of mass 2000 kg traveling with 30 m/sec? 40

Explanation / Answer

1):as from above data we have highet=S=0.92m

Time taken to reach ground=0.43s

Final speed=6.5m/s=v

We have acceleration due to gravity=9.8m/s=a

And let initial speed=u

So from equation of motion

V=u +at

6.5=u +9.8*0.43

u=6.5-4.212

u=2.288 m/s.

2):momentum =mass(kg) x velocity (m/s)

Momentum =2000*30=60000kg.m/s

3):the value of g, acceleration due to gravity is 9.8m/s².

4):from equation of motion we have v²=u²+2as where v=final velocity, u=initial velocity, a=acceleration and s=distance.

As we can see the final velocity depends only on acceleration due to gravity, g, as all other parameters are same in both the cases. But g depends on earth and not on the falling bodies which means that g will be also equal in both the cases and so will be the final velocity. Thus the statement is true.

6): put value of s i.e distance in above formula we get

V²=0² +2(9.8)1000

V²=19600

V=140m/s.

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