Physics Homework Please Help ASAP 2 -2 points SerCP11 18.P004 My Notes Ask Your

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Physics Homework Please Help ASAP

2 -2 points SerCP11 18.P004 My Notes Ask Your Teacher A battery with a 0.128 internal resistance supplies 17.7 w of total power with a 8.21 V terminal voltage. Determine the current I (in A) and the power PR (in w) delivered to the load resistor. Enter your answers to at least three significant figures.) HINT (a) the current I (b) the power PA Need Help? L Read it-ll watch. 3. -/4 poi 0 nts SercP11 18.P 01B. My Notes Ask Your Te Consider the following figure. Note: The currents are not necessarily in the direction shown. (Assume R1 = 32.0 Q, R2 8.5 , and V= 21 V. Ri 2111 R2 (a) Find the current in each resistor of the figure above by using the rules for resistors in series and parallel. 8.5 32.0 24 (b) Write three independent equations for the three currents using Kirchoffs laws: one with the node rule; a second using the loop rule through the battery, the 8.5-2 resistor, and the 24.0-a resistor; and the third using the loop rule through the 32. and 24.0- resistors. Solve to check the answers found in part a Submit a e with a maximum size of 13

Explanation / Answer

2.
given
r = 0.128 ohm
P = 17.7 W
V = 8.21 V
i = P/E
and
V = E - ir
hecne
8.21 = 17.7/i - i*0.128
0.128i^2 + 8.21i - 17.7 = 0
i = 2.0879397 A
Pr = Vi = 17.14198 W

3. R1 = 32 ohm
R2 = 8.5 ohm
V = 21 V

a. then from kirchoff's law
V = I2*R2 + I1*R1
and
I1R1 = 24*I24

I24 + I1 = I2

solving this
32 ohm -> I1 = 0.405 A
8.5 ohm -> I2 = 0.945 A
24 ohm -> I24 = 0.54 A

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