An airplane of mass 11200 kg is flying in a straight line at a constant altitude
ID: 1582118 • Letter: A
Question
An airplane of mass 11200 kg is flying in a straight line at a constant altitude and with a speed of 530.0 km/hr. The force that keeps the airplane in the air is provided entirely by the aerodynamic lift generated by the wings. The direction of this force is perpendicular to the wing surface. Calculate the magnitude of the lift generated by the wings of this airplane.
1.10×105 N
To change the direction of the plane, its wings are banked. If the wings of the plane are banked 37.5° to the horizontal, what is the radius of the circle in which the plane will be flying? Assume that the speed remains 530.0 km/hr during the turn and that the magnitude of the lift provided by the wings is unchanged.
What is the magnitude of the vertical acceleration that the airplane experiences as a result of the turn?
Explanation / Answer
The weight is 11200*g which is 1.1*10^5 N
That will also be the magnitude of the lift during regular flight.
With the wings banked, the horizontal component of the lift is:
1.1*10^5 * sin40 = mv^2 /
= 11200*(530/3.6)^2 / [1.1*10^5 * sin37.5]
= 3625.14 m
= 3.625 km