Block 1 (m1 = 7 kg) is resting on top of block 2 (m2 = 3 kg) on the surface of a
ID: 1582157 • Letter: B
Question
Block 1 (m1 = 7 kg) is resting on top of block 2 (m2 = 3 kg) on the surface of a table. A rope pulls vertically up on block 1 with force 2 N On a sheet of paper, draw the free body diagrams for block 1 and block 2 using the two-subscript notation from class. After completing the free body diagrams, enter below each force and its x & y-components. Remember that the x-component is the "" component and the y-component is the "j" component Weight force on block 1 by Earth Submit Answer Tries 0/3 Tension force on block 1 by Rope Submit Answer Tries 0/3 Normal force on block 1 by block 2 N12 = Submit Answer Tries 0/3 FORCES on BLOCK Weight force on block 2 by Earth Submit Answer Tries 0/3 Normal force on block 2 by block 1 N21 = Submit AnswerTries 0/3 Normal force on block 2 by Surface Submit Answer Tries 0/3Explanation / Answer
Force on Block 1)
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Weight force on block 1 by Earth,
W1E = 0 i + (-m1*g) j
= 0 i + (-7*9.8) j
= 0 i + (-68.6) j
Tension force on block1 by Rope,
T1R = 0 i + 2 j
Normal force on block1 by block 2
N12 = 0 i + (m1*g - 2) j
= 0 i + (7*9.8 - 2) j
= 0i + 66.6 j
Force on Block2
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Weight force on block 2 by Earth,
W2E = 0 i + (-m2*g) j
= 0 i + (-3*9.8) j
= 0 i + (-29.4) j
Normal force on block 2 by block 1,
N21 = -N12
= 0 i + (-66.6) j
Normal force on block 2 by surface,
N2S = 0 i + (m1*g + m2*g - 2) j
= 0 i + (7*9.8 + 3*9.8 - 2) j
= 0 i + 96 j