Problem 6.14-Enhanced-with Feedback Part A hshorttrack speed skating lhehek has

Question

Problem 6.14-Enhanced-with Feedback Part A hshorttrack speed skating lhehek has straight sectors and emicircles 16 m in diameter Assume that a 66 kg skater goes around the tum at a constant 12 m/s What is the horinontal force on the skater? Express your answer to two significant figures and include the appropriate units Figure 1) You may want to review (Pages 164-169) F Value Units Previous Answers Request Answer C Incorrect Try Again; 4 attempts remaining PartB Figure What is the ratio of this force to the skaters weight? Express your answer using two significant figures Return to Assgreere Prowde Feedback 889 3 4 5

Explanation / Answer

part A

horizontal force F = centripetal force = m*v^2/r

m - mass of skater = 66 kg

v = speed of skater = 12 m/s

r = radius of semi circle = D/2 = 16/2 = 8 m

horizontal force F = 66*12^2/8

horizontal force F = 1188 N = 12*10^2 <<<------ANSWER

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part B

skater's weight W = m*g = 66*9.8 = 6.5*10^2

ratio F/W = 12*10^2/6.47*10^2 = 1.8 <<-----ANSWER

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