Class Management i Help Newton\'s Laws Begin Date: 3/1/2018 12:01:00 AM--Due Dat
ID: 1585501 • Letter: C
Question
Class Management i Help Newton's Laws Begin Date: 3/1/2018 12:01:00 AM--Due Date: 3/11/2018 11:59:00 PM End Date: 3/29/2018 11:59:00 PM (6%) Problem 6: A flea (of mass 6 × 10-7 kg) jumps by exerting a force of 1.25 × 10-5 N straight down on the ground. A breeze blowing on the flca parallel to the ground exerts a force of 0.48 x 10-6 N on the flea. Randomized Variables fl = 1.25 x 10-5 N h=0.48 x 10-6 N 50% Part (a) Find the direction of the acceleration of the flea in degrees relative to the vertical. Grade Summary Potential 98 % tan() ( acos0 cos0 sin Submissions Attempts remaining: 6 (1% per attempt) detailed view cotanasin) atan acotan sinh0 cosh tanhO cotanhO e Degrees Radians 0 1% 1% Submit I give up! Hints: 4 for a 0% deduction. Hints remaining: 0 Feedback: 0% deduction per feedback. Draw a free body diagram. How are these forces related to its acceleration? How many forces are there? Use Newton's second law Submission History Feedback Hints -Draw a free body diagram. -How are these forces related to its acceleration? Ho Answer = 11.02 Totals 1% 0% 0% | 1% w many forces are there? Use Newton's second law, 0% 0% 0 0627 1% 2% 0% 0% 1% 2% Totals | 50% Part (b) Find the magnitude of the net force acting on the flea in Newtons All content 2018 Expert TA,Explanation / Answer
a)
Net Force in X-direction
Fnet,x=f2=0.48*10-6 N
Net force in Y-direction
Fnet,y=f1-mg =1.25*10-5-(6*10-7)*9.81 =6.614*10-6 N
Direction
o=tan-1(FY/Fx) =tan-1(6.614/0.48) =85.85o
Direction relative to vertical =90-85.85=4.15o
b)
Magnitude
F=sqrt[Fx2+FY2] =6.63*10-6 N