Please answer all questions. 7.-12 points OSUniPhys1 29.6.WA 039.Tutorial. My No

Question

Please answer all questions.

7.-12 points OSUniPhys1 29.6.WA 039.Tutorial. My Notes Ask Your Teacher You wish to construct a solenoid with a diameter of 2.00 cm that will produce a magnetic field of 7.60 × 10-2 T at its center when a current of 12.0 A is passing through the coils. You want the resistance of the coil wire to be 2.20 . The resistivity of the wire used is 1.70 × 10-8 -m (at 20.0°C), and you are using a wire that has a cross sectional area of 3.14 × 10-8 m2. (Note that this solenoid may not necessarily be so tightly wound that the adjacent loops of wire will touch each other. Nonetheless, you may assume that it behaves like an ideal solenoid.) Determine the following (a) number of turns needed on the solenoid turns (b) length of the solenoid

Explanation / Answer

a)

Resistance of a wire is given by

R=pL/A

Length of the wire is

=>L=RA/p =2.2*(3.14*10-8)/(1.7*10-8)

L=4.06 m

Total Number of turns

N=4.06/(pi*0.02)

N=64.7 =65 turns

b)

Magnetic field of a solenoid is given by

B=uonI

0.076 =(4pi*10-7)*n*12

n=5040 turns

Length of the solenoid is

L=65/5040

L=0.0129 m

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