Please solve and show all work. Thank you! Coulombs Law and Electric Fields Begi
ID: 1586675 • Letter: P
Question
Please solve and show all work. Thank you!
Coulombs Law and Electric Fields Begin Date: 1/25/2016 12:00:00 AM Due Date: 2/5/2016 12:00:00 AM End Date 2/5/2016 12:00:00 AM (9%) Problem 10: A simple and common technique for accelerating electrons is shown in the figure, where there is a uniform electric field between two plates. Electrons are released, usually from a hot filament, near the negative plate, and there is a small hole in the positive plate that allows the electrons to pass through. Randomized Variable E 2.35 x 104 N/C Otheexpertta.com 2.35 x 104 NIC. Express your A 100% Part (a) Calculate the horizontal component of the acceleration of the electron if the field strength is answer in m/s and assume the electric field is pointing in the negative x-direction as shown in the figure. Grade Summary Deductions 0%Explanation / Answer
We know that Force = qE
q =charge of electron= 1.6 x 10-19C and E = 2.35 x 104 N/C given
F = 1.6 x 10-19* 2.35 x 104 = 3.76 x 10-15N
We also know that F = m*a and mass of electron m = 9.1 x 10-31 kg
hence acceleration a = F/m = 3.76 x 10-15N / 9.1 x 10-31 kg = 4.131 x 1015 m/s2..........Ans.