Part A What is the mass of water before the hot iron is put into the cup? Expres

Question

Part A

What is the mass of water before the hot iron is put into the cup?

Express your answer using three significant figures.

230

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Correct

Part B

How much energy is required to melt all of the ice? (Signs matter!)

11.7

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Part C

How much energy is required to raise the temperature of the melted ice and water and copper cup to 30 C? (Signs matter!)

34.3

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Part D

How much energy leaves the iron in the form of heat? (Signs Matter!)

-46.0

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Part E

What was the initial temperature of the iron?

C

NEED ANSWER FOR PART E!!!!

230

Explanation / Answer

E)

heat lost by iron = - 46 kJ =- 46000 J

m = mass of iron = 185 g

c = specific heat of iron = 0.45

initial Temperature = Ti

Final Temperature = Tf

Q = m c (Tf - Ti)

- 46000 = 185 (0.45) (30 - Ti)

Ti = 582.6

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